What is the electron configurations of the gallium ion

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

Explanation:

Gallium is present in group 13.

It has 3 valance electrons.

Electronic configuration:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p¹

There are two possibilities of gallium to form cation.

By removing one 4p electron to form Ga +1 cation.

By removing two 4s electrons and one 4p to form Ga +3 cation.

Gallium is preset in group thirteen that's why common oxidation state is +3.

Electronic configuration of Ga⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p⁰

Electronic configuration of Ga³⁺:

Ga = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰ 3d¹⁰ 4p⁰

i dont know

explanation:

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.