Fe + cuso4 cu + fe2(so4)3 is a balanced equation for the redox reaction true false

False. The balance equation for the redox reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

Explanation:

Let's think the half reactions:

Fe → Fe³⁺  +  3e⁻

The Fe increase the oxidation state. This is the oxidation, where Fe changes from 0 to +3

Cu²⁺  + 2e⁻ → Cu

This is the reduction. Cu changes from 2+ to 0

We multiply the half reaction x2 and x3 to balance the electrons

2Fe → 2Fe³⁺  +  6e⁻

3Cu²⁺  + 3e⁻ → 3Cu

And we sum both

2Fe  + 3Cu²⁺  + 6e⁻ → 3Cu + 2Fe³⁺  +  6e⁻

The electrons are cancelled, so the balance reaction is:

2Fe  + 3CuSO₄ → 3Cu + Fe₂(SO₄)₃

False.

Explanation:

The balanced equation is:

2Fe + 3CuSO4 > 3Cu + Fe2(SO4)^3

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

if you're asking what comes out, it's steam.