\ce{zn + cucl2 -> zncl2 + cu}zn+cucl2 zncl2 +cu
how many moles of \ce{zncl2}znclx 2 will be produced from 21.0 \text{ g}21.0 g21, point, 0, start text, space, g, end text of \ce{zn}znz, n, assuming \ce{cucl2}cuclx 2 is available in excess

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.