N2(g) + 3h2-> 2nh3(g) how many grams of ammonia (nh3) can be produced from the reaction of 28.0 g of n2 and 25.0 g of h2?

34 g of NH₃ were produced in the reaction

Explanation:

N₂ (g)   +  3H₂ (g)  →  2NH₃ (g)

Moles of N₂ → 28 g / 28 g/m = 1 mol

Moles of H₂ → 25g / 2 g/m = 12.5 moles

Clearly, the limiting is the nitrogen.

1 mol of N₂ produced 2 moles of ammonia

So, If I have 1 mol, I'll produce the same amount

2 moles of NH₃ = Mol . Molar mass

2 m  . 17 g/m = 34 g

the answer would be a

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.