If the dimensions of a cube-shaped cell with a volume of 1 pm were to
double, what would be the new surface area of the cell?
o a: 12 um
o b. 24 uma
o c. 6um
o d. 3 um

B

Explanation:

Assuming the units are all supposed to be the same

A cube shaped cell with a 1 um³ volume would have a dimensions of 1 x 1 x 1   (because volume = length x width x height and 1 x 1 x 1 =1)

If we double the dimensions, we have a cube with the dimensions 2 x 2 x 2.

The surface area of each face of the cube is the length x width, so 2 x 2. This means the surface area of each face of the cube is 4 um².

There are 6 faces of a cube, so the total surface area is 6 x 4 um² = 24 um².

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frequency, z, and the collision density, z, in carbon dioxide (co2), r 180 pm at 30 °c and 120 kpa