How many moles of sodium can be produced if 378.3 grams of sodium azide is used

5.82 moles of sodium will produced.

Explanation:

Given data:

Mass of sodium azide = 378.3 g

Moles of sodium produced = ?

Solution:

Chemical equation:

2NaN₃   →   2Na  + 3N₂

Moles of sodium azide:

Number of moles = mass/ molar mass

Number of moles = 378.3 g/ 65 g/mol

Number of moles = 5.82 mol

Now we will compare the moles of sodium azide and sodium.

                          NaN₃      :       Na    

                             2          :         2

                            5.82      :        5.82

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.