When glucose is consumed, it reacts with oxygen in the body to produce carbon dioxide, water, and energy. how many grams of carbon dioxide would be produced if 45 g of c6h12o6 completely reacted with oxygen?

66g

Explanation:

The first step to solving this problem is by writing a balanced chemical reaction.

Here we have glucose reacting with oxygen to give carbon iv oxide and water plus energy.

C6H12O6 + 6O2 —-> 6CO2 + 6H2O + energy

From the chemical reaction, we can see that 1 mole of glucose yielded 6 moles of carbon iv oxide. This is the theoretical relation

Now, we need to get what happened actually. Firstly, we get the number of moles of glucose reacted. This can be obtained by dividing the mass by the molar mass. The molar mass of glucose is (6 * 12) + (12 * 1) + (6 * 16) = 72 + 12 + 96 = 180g/mol

The number of moles is thus 45/180 = 0.25 mole

Now we proceed to get the number of moles of CO2 produced.

Since 6 moles of CO2 were produced from one mole of glucose, the number of moles of glucose produced is thus 6 * 0.25 = 1.5 moles

Since we have the number of moles of CO2 now, we need to know the molar mass to enable us get the mass

The molar mass of CO2 is 12 + 2(16) = 44g/mol

The mass yielded is thus 1.5 * 44 = 66g

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c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.