8oz bottle of dr. pepper made with imperial cane sugar (c12h22o11) contains 27 g of sugar in 236.6 ml of water. what is the molarity of the solution with respect to cane sugar?

0.33M

Explanation:

Molarity is asking, in Laymens terms:

"If I took a litre of this stuff, how much stuff is gonna be in it?"

Diving deeper, we use litres instead of millilitres or nanolitres because that's usually what we're working with. We use moles rather than mass because mass varies; different substances have different molar masses, so describing something in g/L makes no sense if you're comparing two different solutions.

Anyway, go find the number of moles:

n=m/mm

n=27g/342.34g/mol

n=0.078870mol

The next question you've gotta ask yourself is:

What if I had a litre of it?

V = 0.2366L

M=n/V

M=0.078870mol/0.2366L

M=0.33M

1.consider the following balanced equation and answer parts a through. show calculations for each part.  

3 ag(s) + 4 hno3(aq) → 3 agno3(aq) + no(g) + 2 h2o(l)  

a. calculate the number of moles of agno3 produced by the reaction of 3 moles of ag with excess hno3. if the number to the left of the compound represents the number of moles of the compound which are present, then 3 moles of ag react with 4 moles hno3 to produce 3 moles agno3 (aq).

so the answer to a would be 3 moles.

b. calculate the number of moles of agno3 produced by the reaction of 108 grams of ag with excess hno3.  

i'm not sure how to plug in the grams of silver into an equation using moles to find how many moles are produced.

c. calculate the number of grams of agno3 produced by the reaction of 108 grams of ag with excess hno3  

d. calculate the number of moles of no produced as a byproduct of the reaction of 108 grams of ag with excess hno3.  

e. calculate the number of grams of no produced as a byproduct starting with 108 grams of ag and excess hno3.  

explanation: