What is the boiling point of benzene if the external pressure is 5500 torr? Hvap Benzene = 30.72 kJ/mol Normal boiling point of 80.1oC R = 8.314J/ mol K

The boiling point of benzene at given external pressure is 162.45°C

Explanation:

To calculate the boiling point of benzene, we use the Clausius-Clayperon equation, which is:

where,

= initial pressure which is the pressure at normal boiling point = 760 torr

= final pressure which is external pressure = 5500 torr

= Enthalpy of vaporization = 30.72 kJ/mol = 30720 J/mol     (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

= initial temperature or normal boiling pont =

= final temperature = ?

Putting values in above equation, we get:

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:

Hence, the boiling point of benzene at given external pressure is 162.45°C

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