Calculate the mass of H2OH2O produced by metabolism of 1.6 kgkg of fat, assuming the fat consists entirely of tristearin (C57H110O6C57H110O6), a typical animal fat, and assuming that during metabolism, tristearin reacts with O2O2 to form only CO2CO2 and H2OH2O.

1779.8g of H2O

Explanation:

C57H110O6 + O2 —> CO2 + H20

To calculate the amount of water(H2O) produced by the reaction of 1.6Kg tristearin(C57H110O6) and O2, we must first balance the equation.

To do so, add 2 in front of C57H110O6, 163 in front of O2, 114 in front of CO2 and 110 in front of H2O i.e

2C57H110O6 + 163O2 —> 114CO2 + 110H20

Next, we have to calculate the mass of tristearin(C57H110O6) that reacted and the mass of water produced from the balanced equation. This can be done by:

MM of C57H110O6 = (57x12) + (110x1) + (6x16) = 684 + 110 + 96 = 890g/mol

Mass conc of C57H110O6 = 890 x 2 = 1780g

MM of H2O = (2x1) + 16 = 18g/mol

Mass conc of H2O = 110 x 18 = 1980g

Next, we will find the amount of water produced by 1.6Kg(i.e 1600g) of tristearin(C57H110O6). This is done by:

From the equation,

1780g of C57H110O6 produced 1980g of H2O.

Therefore 1600g of C57H110O6 will produce = (1600x1980)/1780 = 1779.8g of H2O

plants need sunlight, water, and carbon dioxide to make food. plants use the raw materials of water, nutrients they absorb from soil, and carbon dioxide to make sugars the plant can use. energy from the sun and chlorophyll are also needed.

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.