A driver blows 0.75 -L air bubble 10 m under water. As it rises to the surface, the pressure goes from 2.25 atm to 1.03 atm. What will be the volume of air in the bubble at the surface ?

1.64 L

Explanation:

P₁V₁ = P₂V₂

P₁ = 2.25 atm

V₁ = 0.75 L

P₂ = 1.03 atm

V₂ = ?

(2.25 atm)(0.75 L) = (1.03 atm)V₂

[(2.25 atm)(0.75 L)]/(1.03 atm) = V₂

V₂ = 1.64 L

ill try to . no promises tho.

explanation:

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