Chemistry, 22.02.2020 01:27 temperent6049
Thallium(I) is oxidized by cerium(IV) as follows:
Tl+(aq) + 2Ce^4+(aq) > Tl^3+(aq) + 2Ce^3+(aq)
The elementary steps, in the presence of aqueous Mn(II), are as follows:
Step 1: Ce^4+ + Mn^2+ > Ce^3+ + Mn^3+
Step 2: Ce^4+ + Mn^3+ > Ce^3+ + Mn^4+
Step 3: Tl^+ + Mn^4+ > Tl^3+ + Mn^2+
(a) Identify the catalyst, intermediates, and the rate-determining step if the rate law is rate = k[Ce^4+][Mn^2+](b) Explain why the reaction is slow without the catalyst.(c) Classify the type of catalysis (homogeneous or heterogeneous).
Answers: 3
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Thallium(I) is oxidized by cerium(IV) as follows:
Tl+(aq) + 2Ce^4+(aq) > Tl^3+(aq) + 2Ce^3...
Tl+(aq) + 2Ce^4+(aq) > Tl^3+(aq) + 2Ce^3...
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