Consider aqueous solutions of the following coordination compounds: , , , and . If aqueous is added to separate beakers containing solutions of each coordination compound, how many moles of will precipitate per mole of transition metal present? Assume that each transition metal ion forms an octahedral complex.

ch3 [ch2]14cooh

explanation:

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answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

i don't see a text, but i am gonna assume this *orbit* the curved path, usually elliptical, described by a planet, satellite, spaceship, etc., around a celestial body, as the sun.