What mass of Na2SO4 is needed to make 2.0 L of 3.0 M solution (Na = 23 g; S = 32 g; O = 16 g)

Thanks!

852g

Explanation:

From the question given, we obtained the following information:

Molarity = 3M

Volume = 2L

Mole =?

First, we need to find the number of mole of Na2SO4 present in 2L of the solution. This is achieved by doing the following:

Molarity = mole /Volume

Mole = Molarity x Volume

Mole = 3 x 2 = 6moles

Next, we'll find the molar mass of Na2SO4, as illustrated below:

Molar Mass of Na2SO4 = (23x2)+32+(16x4) = 46 + 32 + 64 = 142g/mol

Recall:

Number of mole = Mass /Molar Mass

Mass = number of mole x molar Mass

Mass = 6 x 142 = 852g

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.