What is the concentration (g/L) of an albumin solution made by mixing 0.20 mL of 6.0 g/L solution with 2.84 mL BCG reagent? Assume volumes are additive.

0.39 g/L is the concentration of albumin

Explanation:

We assume volumes additive

0.20 mL (volume of solute) + 2.84 ml (volume of solvent) = 3.04 mL (volume of solution)

Let's determine thee mass of solute. We first convert, the mL to L.

0.20 mL. 1 L/1000mL = 0.0002 L

We use the concentration to determine the mass → 0.0002 L . 6 g/L =

0.0012 g of albumin.

This is are the mass of solute in our solution, which has a volume of 3.04 mL. Let's convert the mL to L → 3.04mL. 1 L/1000mL = 0.00304 L

Concentration (g/L) = 0.0012 g /  0.00304 L = 0.39 g/L

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