Now consider the decomposition of dinitrogen monoxide. N2O(g) → N2(g) + ½ O2(g) rate = k[N2O]2 Starting with an initial concentration of 1.0 M, what is the half-life of the reaction?

The Half life is equal to the inverse of the rate constant (1/k).

Explanation:

The half life of any reaction is the amount of time it takes to consume half of the starting material.

For a second-order reaction, the half-life is inversely related to the initial concentration of the reactant (A).

It is mathematically given as;

t1/2 = 1 / k[A]o

where;

t1/2 = Half life

k = Rate constant

[A]o = Initial Concentration

Since the initial concentration is 1.0 M;

Half life = 1 / k(1) = 1 / k

The Half life is equal to the inverse of the rate constant.

gold is my favorite solid.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.