A 10.0 mL 10.0 mL aliquot is removed from the described stock solution and diluted to a total volume of 100.0 mL. 100.0 mL. Calculate the molarity of the dilute solution.

The molarity of the dilute solution is 0.5 M.

The given parameters;

The molarity of the dilute solution is calculated as follows;

where;

D.F is dilute factor

The dilute factor of the given solution is calculated as follows;

Thus, the molarity of the dilute solution is 0.5 M.

"Your question is incomplete, it seems to be missing the following information":

A 10.0 mL of a liquid is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.

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The given question is incomplete. The complete question is:

A 10.0 mL aliquot is removed from the described stock solution with molarity of 5M and diluted to a total volume of 100.0 mL. Calculate the molarity of the dilute solution.

0.5 M

Explanation:

where,

= molarity of stock solution = 5 M

= volume of stock solution = 10.0 ml ml

= molarity of dilute solution = ?

= volume of  dilute solution = 100.0 ml

Putting in the values we get:  

Thus the molarity of the dilute solution is 0.5 M

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890