Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depression constant () for water is 1.86

The freezing point of solution is -0.454°C

Explanation:

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

To calculate the depression in freezing point, we use the equation:

Or,

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

= molal freezing point elevation constant = 1.86°C/m

= Given mass of solute (KCl) = 5.0 g

= Molar mass of solute (KCl) = 74.55 g/mol

= Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

Hence, the freezing point of solution is -0.454°C

true

explanation:

who knows

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.