Chemistry, 16.03.2020 22:22 fordalolz1553

Problem Page Question Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a flask with of ammonia gas and of oxygen gas, and when the mixture has come to equilibrium measures the partial pressure of water vapor to be . Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture. Round your answer to significant digits. Clears your work. Undoes your last action. Provides information about entering answers.

Answers: 2

Show answers

Answers

Answer from: xaniawashington

The question is incomplete, here is the complete question:

Ammonia has been studied as an alternative "clean" fuel for internal combustion engines, since its reaction with oxygen produces only nitrogen and water vapor, and in the liquid form it is easily transported. An industrial chemist studying this reaction fills a 500 mL flask with 4.8 atm of ammonia gas and 1.9 atm of oxygen gas at 33 degress Celsius.

He then raises the temperature, and when the mixture has come to equilibrium measures the partial pressure of nitrogen gas to be 0.63 atm. Calculate the pressure equilibrium constant for the combustion of ammonia at the final temperature of the mixture.

Round your answer to 3 significant digits. Clears your work. Undoes your last action. Provides information about entering answers.

The value of pressure equilibrium constant for the given reaction is 0.132

Explanation:

We are given:

Initial partial pressure of ammonia gas = 4.8 atm

Initial partial pressure of oxygen gas = 1.9 atm

Equilibrium partial pressure of nitrogen gas = 0.63 atm

The chemical equation for the reaction of ammonia and oxygen gas follows:

$4NH_3(g)+3O_2(g)\rightarrow 2N_2(g)+6H_2O(g)$

Initial: 4.8 1.9

At eqllm: 4.8-4x 1.9-3x 2x 6x

Evaluating the value of 'x'

$\Rightarrow 2x=0.63\\\\x=0.315$

So, equilibrium partial pressure of ammonia gas = (4.8 - 4x) = [4.8 - 4(0.315)] = 3.54 atm

Equilibrium partial pressure of oxygen gas = (1.9 - 3x) = [1.9 - 3(0.315)] = 0.955 atm

Equilibrium partial pressure of water vapor = 6x = (6 × 0.315) = 1.89 atm

The expression of K_p for above equation follows:

$K_p=\frac{(p_{H_2O})^6\times (p_{N_2})^2}{(p_{NH_3})^4\times (p_{O_2})^3}$

Putting values in above equation, we get:

$K_p=\frac{(0.63)^2\times (1.89)^6}{(3.54)^4\times (0.955)^3}\\\\K_p=0.132$

Hence, the value of pressure equilibrium constant for the given reaction is 0.132

Answer from: Quest

they are both synthetic elements

explanation:

Answer from: Quest

the dependant variable is spilled water

the independent is the heat

Another question on Chemistry

Chemistry, 21.06.2019 20:30

The balanced chemical equation for this lab is: 3cucl2(aq) + 2al(s) 3cu(s) + 2alcl3(aq) if 10.5 g copper chloride react with 12.4 g aluminum, what is the limiting reactant?

Answers: 3

Answer

Chemistry, 22.06.2019 11:30

Aperfume bottle is dropped in the corner of a room. the odor of the perfume can be detected on the other side of the room. which statement best describes this observation?

Answers: 2

Answer

Chemistry, 22.06.2019 15:20

An alloy contains 66 g of pure zinc. what is the percentage of zinc in the alloy? express your answer to two significant figures and include the appropriate units.

Answers: 1

Answer

Chemistry, 22.06.2019 16:10

Amixture initially contains a, b, and c in the following concentrations: [a] = 0.300 m , [b] = 1.05 m , and [c] = 0.550 m . the following reaction occurs and equilibrium is established: a+2b⇌c at equilibrium, [a] = 0.140 m and [c] = 0.710 m . calculate the value of the equilibrium constant, kc.

Answers: 1

Answer

You know the right answer?

Problem Page Question Ammonia has been studied as an alternative "clean" fuel for internal combustio...

Questions