in the balanced chemical reaction for the combustion of acetylene (used in welding torches), determine at standard temperature and pressure, how many liters of CO2 gas are produced if 10 liters of Oxygen gas are completely consumed?

_2_C2H2 + _5_ O2 --> _4_CO2 + _2_ H2O

please help thx

8L of CO2

Explanation:

The equation for the reaction is given below:

2C2H2 + 5O2 —> 4CO2 + 2H2O

From the equation above,

5L of O2 produced 4L of CO2.

Therefore, 10L of O2 will produce = (10 x 4)/5 = 8L of CO2

Therefore, 8L of CO2 is produce

c. 75.7

i think that is the right

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :