Question 10
Given the reaction C5H12(1) -> C5H8(1) + 2 H2(g).
If 1.50 x 10^22 molecules...
![subject](/tpl/images/cats/himiya.png)
Chemistry, 07.04.2020 03:12 Marcus2935
Question 10
Given the reaction C5H12(1) -> C5H8(1) + 2 H2(g).
If 1.50 x 10^22 molecules of C5 H12 decomposed, the calculation below yields the value for what quantity?
1 mol C5H12
1.50 x 10^22 molec. C5H12 x_
C5H12 1 mol H2
x 2 mol H2
X
2.0 g H2
number of molecules of C5H12
moles of H2
mass of H2
mass of C5H12
![ansver](/tpl/images/cats/User.png)
Answers: 3
![](/tpl/images/ask_question.png)
![](/tpl/images/ask_question_mob.png)
Another question on Chemistry
![question](/tpl/images/cats/himiya.png)
Chemistry, 22.06.2019 08:40
For each of the following compounds, write the formula then predict whether it would be a strong, weak, or non-electrolyte when placed in di water. for the ionic compounds only, put (s) or (aq) after the forrmula formula strong, weak or non electrolyte? a calcium hydroxide b. silver carbonate c. lead(ii) sulfate d. phosphorus trifluoride e. sodium phosphide f barium sulfate g. strontium acetate h. zinc nitrate
Answers: 3
![question](/tpl/images/cats/himiya.png)
![question](/tpl/images/cats/himiya.png)
Chemistry, 22.06.2019 22:30
What if it is did darwin used to support his theory of evolution
Answers: 1
![question](/tpl/images/cats/himiya.png)
Chemistry, 22.06.2019 23:50
Be sure to answer all parts. the following equilibrium constants were determined at 1123 k: c(s) + co2(g) ⇌ 2co(g) k'p = 1.30 × 1014 co(g) + cl2(g) ⇌ cocl2(g) k''p = 6.00 × 10−3 calculate the equilibrium constant at 1123 k for the reaction: c(s) + co2(g) + 2cl2(g) ⇌ 2cocl2(g) 4.68 × 10 9 (enter your answer in scientific notation.) write the equilibrium constant expression, kp:
Answers: 3
You know the right answer?
Questions
![question](/tpl/images/cats/mat.png)
Mathematics, 05.06.2021 02:30
![question](/tpl/images/cats/ekonomika.png)
![question](/tpl/images/cats/mat.png)
![question](/tpl/images/cats/mat.png)
![question](/tpl/images/cats/mat.png)
![question](/tpl/images/cats/mat.png)
![question](/tpl/images/cats/mat.png)
Mathematics, 05.06.2021 02:30
![question](/tpl/images/cats/informatica.png)
Computers and Technology, 05.06.2021 02:30
![question](/tpl/images/cats/informatica.png)
Computers and Technology, 05.06.2021 02:30
![question](/tpl/images/cats/istoriya.png)
History, 05.06.2021 02:30
![question](/tpl/images/cats/mat.png)
![question](/tpl/images/cats/mat.png)
Mathematics, 05.06.2021 02:30
![question](/tpl/images/cats/obshestvoznanie.png)
![question](/tpl/images/cats/mat.png)
Mathematics, 05.06.2021 02:30
![question](/tpl/images/cats/en.png)
![question](/tpl/images/cats/istoriya.png)
![question](/tpl/images/cats/istoriya.png)
History, 05.06.2021 02:30
![question](/tpl/images/cats/en.png)
![question](/tpl/images/cats/User.png)
Engineering, 05.06.2021 02:30