Which of the following bonds will have the smallest difference in electronegativity?

H2

NaF

HBr

HS-

The answer to your question is the first choice (H₂)

Explanation:

Process

Look for the electronegativity of the elements of this exercise

a) H₂ = 2.2 - 2.2 = 0

b) NaF = 3.98 - 0.93 = 3.05

c) HBr = 2.96 - 2.2 = 0.76

d) HS⁻ = 2.58 - 2.2 = 0.38

The molecule that has the smallest difference in electronegativity is H₂

answer; 4 electrons;