A cube of aluminum (Cp = 0.897 J/g•K) has a temperature of 325 K. It is placed in a beaker of cold water. If the aluminum cools to 301 K as the water absorbs 815.7 J of heat, what is the mass of the cube?

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

wher is the rest of the question