.![[Pb^{2+}]=0.0159 M](/tpl/images/0600/3825/89ec5.png)
![[Cl^-]=0.0318 M](/tpl/images/0600/3825/75929.png)
![K_{sp}=[Pb^{2+}][Cl^-]^2](/tpl/images/0600/3825/7fd11.png)
PbCl2 (s) ⇆ Pb2+ (aq) + 2Cl− (aq)
Chemistry, 15.04.2020 00:52 genyjoannerubiera
Consider the dissolution equation of lead(II) chloride.
PbCl2 (s) ⇆ Pb2+ (aq) + 2Cl− (aq)
Suppose you add 0.2307 g of PbCl2 (s) to 50.0 mL of water. In the resulting saturated solution, you find that the concentration of Pb2+ (aq) is 0.0159 M and the concentration of Cl− (aq) is 0.0318 M.
What is the value of the equilibrium constant, Ksp, for the dissolution of PbCl2?
Answers: 3
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You know the right answer?
Consider the dissolution equation of lead(II) chloride.
PbCl2 (s) ⇆ Pb2+ (aq) + 2Cl− (aq)
PbCl2 (s) ⇆ Pb2+ (aq) + 2Cl− (aq)
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