How many milliliters of 0.0850 m naoh are required to titrate 25.0 ml of to the equivalence point?

The given question is incomplete. The complete question is:

How many milliliters of 0.0850 M NaOH are required to titrate 25.0 mL of 0.0720 M HBr to the equivalence point?

21.2 ml

Explanation:

To calculate the volume of base, we use the equation given by neutralization reaction:

where,

are the n-factor, molarity and volume of acid which is

are the n-factor, molarity and volume of base which is NaOH.

We are given:

Putting values in above equation, we get:

Thus 21.2 ml of 0.0850 M NaOH are required to titrate 25.0 mL of 0.0720 M HBr to the equivalence point

oxygen, selenium, tellurium, and polonium.

they're all from the same group as sulfur (group 16).