What is the volume of 3.66 x 1032 molecules of fluorine gas at STP?

1.36x10^10L

Explanation:

Step 1:

Determination of the mole of fluorine that contains 3.66x10^32 molecules. This is shown below:

From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02x10^23 molecules. This implies that 1 mole of fluorine also contains 6.02x10^23 molecules.

Now if 1 mole of fluorine contains 6.02x10^23 molecules,

Therefore, Xmol of fluorine will contain 3.66x10^32 molecules i.e

Xmol of fluorine = 3.66x10^32/6.02x10^23

Xmol of fluorine = 6.08x10^8 moles

Step 2:

Determination of the volume occupied by 6.08x10^8 moles of fluorine.

1 mole of any gas occupy 22.4L at stp. This means that 1 mole of fluorine also occupy 22.4L at stp.

Now if 1 mole of fluorine occupies 22.4L at stp,

Then 6.08x10^8 moles of fluorine will occupy = 6.08x10^8 x 22.4 = 1.36x10^10L

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