If a 95.0 gram sample of metal at 100.0 oC is placed in 50.0 g of water with an initial temperature of 22.5oC and the final temperature of the system is 48.5oC, what is the specific heat of the metal? Group of answer choices

Answer : The specific heat of the metal is,

Explanation

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

where,

= specific heat of metal = ?

= specific heat of water =

= mass of metal = 95.0g

= mass of water  = 50.0 g

= final temperature of mixture =

= initial temperature of metal =

= initial temperature of water =

Now put all the given values in the above formula, we get

Therefore, the specific heat of the metal is,

the formula would be mgso4

mgso[subscript]4