In the following reaction, how many grams of nitroglycerin c3h5(no3)3 will decompose to give 25 grams of co2?
4c3h5(no3)3(l) 12co2(g) + 6n2(g) + 10h2o(g) + o2(g)

the molar mass of nitroglycerin is 227.0995 grams and that of carbon dioxide is 44.01 grams.

4C₃H₅(NO₃)₃ ------> 12CO₂ + 6N₂ +  10H₂O  +  O₂

mol of CO₂  = 

                    = 

mol ratio of  CO₂ :  C₃H₅(NO₃)₃

                    12    :     4

∴  if  mole of CO₂  =  0.568 mol

then   "       "   C₃H₅(NO₃)₃  = 

                                           = 0.189 mol

∴ mass of nitroglycerin  =  mole  *  Mr

                                       =  0.189 mol  *  227.0995 g / mol

                                       =  43.00 g