Calculate the [H^+] of a solution that has a pH of 8.76 *
Round answers to 2 places past the decimal. Use the following format: #.## x 10^-# (there should be a space on either side of the x

The [H⁺] of the solution is 1.74*10⁻⁹ M

Explanation:

pH, short for Hydrogen Potential, is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance. The pH scale ranges from 0 to 14. Values less than 7 indicate the acidity range and those greater than 7 indicate alkalinity or basicity. Value 7 is considered neutral.

The pH is calculated as the negative logarithm (base 10) of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O⁺).

pH= - log [H⁺] = -log [H₃O⁺]

In this case, you know that pH= 8.76.  Replacing in the definition of pH:

8.76 = -log [H⁺]

Solving:

[H⁺]=  10⁽⁻⁸ ⁷⁶⁾

[H⁺]= 1.74*10⁻⁹ M

The [H⁺] of the solution is 1.74*10⁻⁹ M

i know insulin is primary but i dont know the others im sorry

explanation: