Calculate the equilibrium constant K for the following reaction: H2(g) + Cl2(g) ⇋ 2 HCl (g) at equilibrium, [HCl] = 0.50 M, [H2] = 0.75 M, [Cl2] = 0.25 M

K = 1.33

Explanation:

[HCl] = 0.50M

[H₂] = 0.75M

[Cl₂] = 0.25M

equation of reaction,

H₂ + Cl₂ ⇄ 2HCl

K = [Products] / [Reactants]

K = [HCl]² / [H₂][Cl₂]

K = [0.5]² / [0.75][0.25]

K = 0.25 / 0.1875

K = 1.33

The equilibrium constant K is equal to 1.33

im pretty sure its b