Joseph Lister is the surgeon who introduced new principles of cleanliness which transformed surgical practice in the late
1800s. Today, we take it for granted that a surgeon will guard a patient's safety by using aseptic methods. But this was not
always the case and until Lister introduced sterile surgery, a patient could undergo a procedure successfully only to die from
a postoperative infection known as 'ward fever". He read Pasteur's work on microorganisms and decided to experiment using
one of Pasteur's proposed techniques, that of exposing the wound to chemicals. He chose dressings soaked with carbolic acid
to cover the wound and the rate of infection was vastly reduced.
Lister's lowered infection rate was life saving and his principles have since been adopted worldwide. Lister is now known as the
"father of antiseptic surgery." Which of these is NOT an application of Lister's work?
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A)
use of antiseptic on wounds
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B)
surgical handwashing technique
sterilization of surgical instruments
D)
filtration of fluids to eliminate microorganisms

D)  filtration of fluids to eliminate microorganisms

Explanation:

Lister is also called father of antiseptic surgery because he introduced the methods to prevent the growth of microbes and contamination during surgical microbes. He was the professor of surgery. He used carbolic acid which is an antiseptic to clean the exposed wound. He implemented the use of sanitizer for hand-washing, spraying the carbolic acid in the theater, during operations and for sterilizing the instruments.

1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.