![Rate = k [CH_3 Cl] [Cl_2]^{0.5}](/tpl/images/0675/8688/f7f7b.png)
, the rate of backward reaction is given by: ![Rate = k [A]^{a} [B]^{b}\\k = \frac{Rate}{ [A]^{a} [B]^{b}}\\k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}](/tpl/images/0675/8688/ebbf5.png)
![0.014 / [0.05]^a [0.05]^b = 00.029/ [0.100]^a [0.05]^b\\0.014 / [0.05]^a [0.05]^b = 00.029/ [2*0.05]^a [0.05]^b\\0.014 / = 0.029/ 2^a\\2^a = 2.07\\a = 1](/tpl/images/0675/8688/247cc.png)
![0.041 / [0.100]^a [0.100]^b = 0.115 / [0.200]^a [0.200]^b\\0.041 / [0.100]^a [0.100]^b = 0.115 / [2 * 0.100]^a [2 * 0.100]^b\\](/tpl/images/0675/8688/0c6b5.png)
![0.041 = 0.115 / [2 ]^a [2]^b\\ \[[2 ]^a [2]^b = 0.115/0.041\\ \[[2 ]^a [2]^b = 2.80\\\[[2 ]^1 [2]^b = 2.80\\\[[2]^b = 1.40\\b = \frac{ln 1.4}{ln 2} \\b = 0.5](/tpl/images/0675/8688/ae2b8.png)
![k = \frac{Rate}{ [CH_3 Cl]^{a} [Cl_2]^{b}}](/tpl/images/0675/8688/c4a73.png)
then becomes:![k = 0.014 / ( [0.050] [0.050]^(0.5) )\\k = 1.25](/tpl/images/0675/8688/5313f.png)
The tabulated data were collected for this reaction:
CH3Cl(g) + 3Cl2(g) → CCl4(g) + 3HCl(g)
<...
Chemistry, 04.06.2020 13:28 zahinparvez69
The tabulated data were collected for this reaction:
CH3Cl(g) + 3Cl2(g) → CCl4(g) + 3HCl(g)
[CH3Cl] (M) [Cl2] (M) Initial Rate (M/s)
0.050 0.050 0.014
0.100 0.050 0.029
0.100 0.100 0.041
0.200 0.200 0.115
(a) Write an expression for the reaction rate law and calculate the value of the rate constant, k.
(b) What is the overall order of the reaction?
Answers: 3
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