Chemistry, 05.02.2020 06:52 Thania3902

Acompound is 54.53% c, 9.15% h, and 36.32% o. what is its empirical formula?

the molar mass of the compound is 132 amu. what is its molecular formula?

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We are given with a different mass percentages of different elements. we divide first each percentage by the molar mass of each element. Then, divide each by the smallest among them. C has 2, H has 4 adn O has 1. Thus the empirical formula is C2H4O with a molar mass of 44 grams. This is 1/3 od 132 amu. Hence the molecular formula is C6H12O3

Answer from: Kassi07

The empirical formula : C₂H₄O

The molecular formula : C₆H₁₂O₃

Further explanation

The empirical formula is the smallest comparison of atoms of compound forming elements.

A molecular formula is a formula that shows the number of atomic elements that make up a compound.

(empirical formula) n = molecular formula

The principle of determining empirical formula and molecular formula

Determine the mass ratio of the constituent elements of the compound.Determine the mole ratio by dividing the elemental mass with the relative atomic mass obtained by the empirical formulaDetermine molecular formulas by looking for values of n

Percentage of elements A and B in AxBy compounds:

% A in AₓBy = (x x Ar A / Mr AₓBy) x% AₓBy

% B in AₓBy = (y x Ar B / Mr AₓBy) x% AₓBy

It is known about the% mass of each element

To find the empirical formula, we look for its mole ratio (% mass/ its relative atomic mass)

C = 54.53 / 12 = 4.544

H = 9.15 / 1 = 9.15

O = 36.32 / 16 = 2.27

To simplify the comparison as an integer, we divide by the mole ratio of the smallest element

C = 4.544 / 2.27 = 2

H = 9.15 / 2.27 = 4

O = 2.27/2.27 = 1

So the empirical formula:

C₂H₄O

We look for the molecular formula to get the number of atoms making up the compound

(C₂H₄O) n = molecular formula

(2.12 + 4.1 + 16) n = 132

(44) n = 132

n = 3

So molecular formula = C₆H₁₂O₃

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the molar mass of a substance

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Keywords: empirical formula, molecular formula, mass, mole

Acompound is 54.53% c, 9.15% h, and 36.32% o. what is its empirical formula? the molar mass of the

Answer from: Quest

m=9

step-by-step explanation:

7m+8=71 subtract 8 from 71 which is 63 than divide it by 7m equal 9.

Answer from: Quest

personal, she chose to do it.

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Acompound is 54.53% c, 9.15% h, and 36.32% o. what is its empirical formula?

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