How many moles of K+ & PO4^3- ions are present in 20.0 mL of a 0.015 M solution of potassium phosphate?

9.0 × 10⁻⁴ mol of K⁺

3.0 × 10⁻⁴ mol of PO₄³⁻

Explanation:

Step 1: Calculate the moles of potassium phosphate in 20.0 mL of a 0.015 M solution

Step 2: Write the balanced dissociation reaction

K₃PO₄(aq) ⇒ 3 K⁺(aq) + PO₄³⁻(aq)

Step 3: Calculate the moles of K⁺

The molar ratio of K₃PO₄ to K⁺ is 1:3. The moles of K⁺ are 3/1 × 3.0 × 10⁻⁴ mol = 9.0 × 10⁻⁴ mol

Step 4: Calculate the moles of PO₄³⁻

The molar ratio of K₃PO₄ to PO₄³⁻ is 1:1. The moles of PO₄³⁻ are 1/1 × 3.0 × 10⁻⁴ mol = 3.0 × 10⁻⁴ mol

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.