A cylinder rod formed from silicon is 21.3 cm long and has a mass of 5.00 kg. The density of silicon is 2.33 g/cm3. What is the diameter of the cylinder? (the volume of cylinder is given by π r2h, where r is the radius and h is the length)

11.32cm

Explanation:

This question describes a cylinder rod formed from silicon with length 21.3cm and mass 5kg. The density of the silicon is 2.33g/cm3.

To calculate the diameter, the radius is needed. To calculate the radius, the volume is needed. To calculate the volume, the formula: density = mass (m) / volume (V) is used.

Mass = 5kg, which is 5 kg × 1000g = 5000g

Density= 2.33g/cm3

Hence; volume= mass / density

= 5000/2.33

= 2145.9 cm3

Volume of cylinder= πr^2h

Where h= 21.3cm and π= 3.142

That is; r^2 = volume/πh

= r^2 = 2145.9/3.142×21.3

= r^2 = 2145.9/66.9246

= r^2 = 32.06

r= √32.06

r= 5.66cm

If radius of the cylinder is 5.66cm, the diameter is twice of the radius.

That is, diameter (d) = 5.66 × 2

= 11.32 cm

Therefore, the diameter of the cylinder is 11.32cm.

the correct answer is b. a strong acid completely dissociates to its ions when dissolved in water. completely dissociates to and ions. a is incorrect because does not fully ionize to and ions and some remain as the compound . c and d are incorrect because, and do not fall into the category of bronsted lowry acids. a bronsted lowry acid is a proton donor and since both molecules do not have a proton to donate they are not bronsted lowry acids. likewise,   if we use the lewis acid definition, they cannot be acids. a lewis acid is an electron pair acceptor. both and have a complete octet so can not accept any electrons which disqualifies them as acids.