QUESTION 17 If the theoretical yield of the following reaction is 3.43g of MgO and the actual yield is 2.48g of Mgo, what is the percent yield?
O 1.38%
O 72.3%
O 0.723%
138%

72.3%

Explanation:

The following data were obtained from the question:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.?

Percentage yield of a reaction can simply be obtained by dividing the actual yield by the theoretical yield multiplied by 100. This is illustrated below:

Percentage yield = Actual yield /Theoretical yield × 100

Thus, we can obtain the percentage yield of MgO as follow:

Theoretical yield of MgO = 3.43 g

Actual yield of MgO = 2.48g

Percentage yield of MgO =.? Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 2.48/3.43 × 100

Percentage yield = 72.3%

Therefore, the percentage yield of MgO is 72.3%.

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