A certain compound contains 4.0 g of calcium and 7.1 g of chlorine. Its relative molecular mass is 111. Find its empirical and molecular formulas

Given :

A certain compound contains 4.0 g of calcium and 7.1 g of chlorine.

Its relative molecular mass is 111.

To Find :

Its empirical and molecular formulas.

Solution :

Moles of calcium , .

Moles of chlorine , .

The ratio calcium and chlorine is 1 : 2 .

So , the empirical formula is .

Now , molecular mass of is :

So ,

Therefore , the molecular formula is also .

Hence , this is the required solution .

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

16

explanation:

the marks go by 4s