What mass of a 0.583 molar solution of iron(III) nitrate is needed to obtain a) 0.0200 moles of iron(III) nitrate, b) 0.0500 moles of Fe3+ ions, c) 0.00300 moles of nitrate ions? please

the millers tale is the answer.

it's c. elements are placed in rows based on how may valencies electrons have.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.