What is the speed of each vehicle? (Remember S=d/t) A: 50 km/h, B: 40 km/h

A:5 km/h, B: 2 km/h

A: 10 km/h, B: 5 km/h

A: 20 km/h, B: 10 km/h

Answer : The correct option is A: 20 km/h, B: 10 km/h

Explanation :

Speed : It is defined as the distance traveled per unit time.

Formula used:

where,

S = speed

d = distance

t = time

First we have to calculate the speed of vehicle A.

Given:

Distance of vehicle A = 50 km

Time of vehicle A = 2.5 hr

Now putting all the given values in the above formula, we get:

Now we have to calculate the speed of vehicle B.

Given:

Distance of vehicle B = 50 km

Time of vehicle B = 5 hr

Now putting all the given values in the above formula, we get:

Therefore, the speed of vehicle A and B is 20 km/hr and 10 km/hr respectively.

r just means there's a number of carbon in teh chain. for example rcooh means that after x number of carbon, the chain ends with cooh.

explanation:

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol