If 550 grams of KClO3 breaks down and produces 175 grams of KCl, how many grams of O2 are produced?

215.51 g of O2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCl + 3O2

Next, we shall determine the mass of KClO3 that decomposed and the mass of O2 produced from the balanced equation. This is illustrated below:

Molar mass of KClO3 = 39 + 35.5 + (16×3)

= 39 + 35.5 + 48

= 122.5 g/mol

Mass of KClO3 from the balanced equation = 2 × 122.5 = 245 g

Molar mass of O2 = 16 × 2 = 32 g/mol

Mass of O2 from the balanced equation = 3 × 32 = 96 g

From the balanced equation above,

245 g of KClO3 decomposed to produce 96 g of O2.

Finally, we shall determine the mass of O2 produced by the decomposition of 550 g of KClO3. This can be obtained as follow:

From the balanced equation above,

245 g of KClO3 decomposed to produce 96 g of O2.

Therefore, 550 g of KClO3 will decompose to produce =

(550 × 96)/245 = 215.51 g of O2.

Therefore, 215.51 g of O2 were obtained from the reaction.

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.