Lead(ii) sulfide, pbs, reacts with oxygen gas to produce lead(ii)oxide and dioxide. if 0.500 moles of o2 were consumed using this chemical reaction, how much of lead(ii)would be produced?

The balanced chemical reaction is written as:

PbS + 3/2O2 = PbO + SO2

We  are given the amount of oxygen to be consumed in the reaction. We use this amount for the calculations. We do as follows:

0.500 mol O2 ( 1 mol PbO / 3/2 mol O2) = 0.33 mol PbO is to be produced

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