A gas expands from 285 mL to 789 mL at constant temperature. How much work is done by the gas (joules) if it expands against a constant pressure of 6.00 atm?

-306j

Explanation:

For this question we define an equation:

W = -Pext(Vj-Vi)> eqn 1

P = 6atm

Vi = 285 ml

We convert it to litre

= 285/1000 mL

= 0.285 L

Vj = 789 mL

When converted to litre

= 789/1000 mL

= 0.789 L

These values are all going to be put values in the eqn 2 above

W = -Pext(Vj-Vi)

W = -6.0x (0.789L - 0.285L)

W = -3.024

W = -3.024 x 101.33 J

This gives us the answer

W = -306 J

Thank you!

-306 J

93.2 ml + 3920 ml = 4013 ml total  

(93.2 ml) * (2.03 m) / (4013 ml) = 0.0471 m

the volume in in l of the diluted solution would be 0.0471 m.