How many moles of Na2SO4 are in 0.140 m aqueous solution that was prepared with 2.30 kg of water?

0.322 mols of NaSO4

Explanation:

Molality = Mols of Solute / kg of Solvent

Molality is given as 0.140 m = mols/kg

kg of solution is given as 2.30 kg

Mols of Solute = Molality * kg of Solvent

Mols of Solute =

Mols of Solute = 0.322 mols

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the answer is 1 i believe