6. What volume does 14.0 g of Hydrogen gas (Hz) take up at a temperature of 30°C and a pressure of 120 kPa?
Note: Use Ideal gas law. R=8.31 (kPa x L)/(mol x K)

V = 146.87 L

Explanation:

Given data:

Mass of sample = 14.0 g

Pressure of sample = 120 kpa

Volume of gas = ?

Temperature of gas = 30°C

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles = 14.0 g/ 2 g/mol

Number of moles = 7 mol

Pressure of gas:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 8.31 KPa.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

30+273 = 303 K

by putting values,

120 KPa × V = 7 mol × 8.31 KPa.L/ mol.K  × 303 K

V = 17625.51 KPa .L/ 120 KPa

V = 146.87 L

explanation:

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