How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm and 25°C? C°C +273 = °K) (R=0.0821 L. atm/mol-K)

We are given:

Volume of Gas (V) = 2.5L

Pressure (P) = 1.2 atm

Temperature (T) = 25°C  OR 25+273 = 298 K

Universal Gravitational Constant (R) = 0.0821

Solving for number of moles:

From the Ideal Gas Equation,

PV = nRT

(1.2)(2.5) = n(0.0821)(298)           [plugging the given values]

n = [(1.2)(2.5)] / [0.0821*298]

n = 300 / [298*8.21]

n = 0.12 moles

Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C

explanation: it gains negative electrons, therefore becoming negatively charged. as charge cannot be created, nor destroyed, only transferred, this leaves the wool positive. now that they have opposite charges, the two items attract.