If 2.0 ml of water is added to 8.0 ml of a 0.30 m solution to make a new solution with a total volume of 10.0 ml, what is the concentration of the new solution?

Thank you for posting your Chemistry question here at . I hope the answer will help you. The concentration of the new solution is the below:

0.002 L CuSO4 (0.80 mol/L) = 0.0016 mol CuSO4/0.008 L = 0.02 mols/L CuSO4 

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