Please help me understand how to... Calculate the mass of Cr2O3 that can be produced if the reaction of 56.2 g of chromium and sufficient oxygen has a 76.0 % yield.
...Thank you!

Explanation:

Hello!

In this case, according to the reaction:

We can see there is a 4:2 mole ratio between chromium and chromium (III) oxide, this, for the given 56.2 g of chromium, the theoretical yield of the oxide product is computed down below:

Now, considering the 76.0-% yield for this reaction, the actual yield turns out:

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