Calculate each of the following in 0.185 mol of dipropyl ether, (c3h7)2o:
moles of c
moles of o
atoms of h
atoms of c

We have 6 moles of C (2*3=6), 14 moles of H (2*7=14) and 1 mol of O in 1 mol of (C₃H₇)₂O:

Therefore:
1 mol of (C₃H₇)₂O6 moles of C
0.185 moles of (C₃H₇)₂O    x

x=(0.185 moles * 6 moles)/1 mole=1.11 moles

there are 1.11 moles of C in 0.185 moles of dipropyl ether

1 mol of C6.022*10²³ atoms
1.11 moles of C  x

x=(1.11 moles of C *6.022*10²³ atoms)/1 mole of C=6.68 *10²³ atoms

there are 6.68*10²³ atoms of C in 0.185 moles of dipropyl ether.


1 mole of (C₃H₇)₂O14 moles of H
0.185 moles of (C₃H₇)₂O    x

x=(0.185 moles * 14 moles)/1 mole=2.59 moles


 there are 2.59 moles of H in 0.185 moles of dipropyl ether

1 mol 6.022*10²³ atoms
2.59 moles    x

x=(2.59 moles * 6.022*10²³ atoms)/1 mol=1.56*10²⁴ atoms

there are 1.56*10²⁴ atoms in 0.185 moles of dipropyl ether.


1 mol of (C₃H₇)₂O1 moles of C
0.185 moles of (C₃H₇)    x

x=(0.185 moles *1mol)/1 mol=0.185 moles

there are 0.185 moles of O in 0.185 moles of dipropyl ether.