If 15.0 g CH3OH reacts with 10.0 g of CO, which is the limiting reagent and what is the theoretical yield of CH3COOH?

Explanation:

CH₃OH    +    CO    =    CH₃COOH .

32 g           28 g               60 g

CH₃OH = 15 g ;  CO = 10 g

32 g of CH₃OH  reacts with 28 g of CO

15 g of CH₃OH reacts with 28 x 15 / 32 g of CO

= 13.125 g of CO .

CO given = 10 g , so CO is the limiting reagent .

28 g of CO reacts with CH₃OH  to produce 60 g of CH₃COOH

10 g of CO reacts with CH₃OH  to produce 60 x 10 / 28  g of CH₃COOH

CH₃COOH produced = 600 / 28 g = 21.42 g .

is has three carbons, so the answer is propylamine.

meth-

eth-

prop-

but-

pent-

hex-

hept-

oct-

non-

explanation:

the answer is na (sodium)