Copper (II) nitrate and sulfuric acid react to form copper (II) sulfate and nitric acid. If 3.27 moles of copper (II) nitrate react, how many moles of nitric acid will be formed in this reaction?

It could possibly be beneficial if the experiment is successful.

Answer is: the equilibrium  shifts toward the reactants, to the left side of chemical reaction.it is because lead(ii) nitrate dissociates in water: pb(no₃)₂ → pb²⁺(aq) + 2no₃⁻(aq).according to lechatelier's principle, the position of equilibrium moves to counteract thechange (more lead cations, common ion), the position of equilibrium will move so that the concentration ofproducts decrease and concentration of reactants of chemical reaction increase.read more on -